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Re: 3% or 3.5% Tue, 09 September 2003 06:27 Go to previous messageGo to previous message
Robert is currently offline Robert

 
Lt. Junior Grade

Messages: 393
Registered: November 2002
Location: Dortmund, Germany
here it is: Very Happy

Quote:


ZooltaR wrote:
>
> I'm trying to get one SD (Hi Ward!) off my back. He laid several nice
> heavy minefields in my space, with minelayers nested iside. Attempt to
> sweep them "slowly and carefully" will probably result in a minefield
> blasting and the layers moving somewhere else. Thinking about possible
> solutions, I came to the following idea:
>
> Build several cheap destroyers with good firepower and sweeping
> capability. Send 6 of them to the minelayers at Warp 8 (minelayers are
> 60,51 ly away - so no warning for the SD) AS SEPARATE FLEETS. Speed is 2
> "warps" higher than safe, so each of them has 2% chance per ly travelled
> that it hits the mine. In other words, chances it will arrive undamaged
> are .98^60, or 0.2916025.

Nope. Not how it works. The chance of hitting a mine is not checked
seperately for each LY traveled. It is directly additive for each LY
traveled. The chance can go to 100% or more, in which case a hit is
certain (in this case, and warp 8 anything over 50 LY means an automatic
hit). As the help file notes at one point "you *will* hit a mine",
discussing how the percentages add.

But then how come I sometimes go some distance into them and sometimes
another? - might be the rejoinder. This I only gather from testing, and
is not in the help - apparently a "roll" is made for the hit chance, and
the ship goes until the roll is exceeded by the mine hit chance or until
it gets out of the field or completes movement.

So, again, the hit chance doesn't multiply, it *adds*. Which is much
worse. It means the SD can guareentee non-intercept, for example, by
staying far enough away through enough of the right type of mines.

As some one else noted, this is one nice use of speed traps for SD - a
small field near the minelayer will stop anyone going fast enough to
reach the layer. Though they are heavy enough that they will be less
well represented i
...




2b v !2b -> ?

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