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Re: 3% or 3.5% Tue, 09 September 2003 04:39 Go to previous messageGo to previous message
Robert is currently offline Robert

 
Lt. Junior Grade

Messages: 393
Registered: November 2002
Location: Dortmund, Germany
Hm....

I remember some Jason Cawley article that the effect of minefields is additive, not multiplicative. Or in other words:
it is _not_ checked per lightyear! It is checked per whole distance.
Or still in other words:
The chance to hit a minefield can be >100%, so the chance to pass a minefield equals zero if the field is large enough.

I know the spreadsheets calculate it per turn, but I am pretty sure Jason said it is calculated differently, and in most cases he is correct Cool

So... I would say it is chance*warps2fast*ly, and if that is say
3.5% * 4 warps2fast * 10 ly then it is 140% which means you hit in any case.
it is not (100-14)^10 to pass undamaged...

Just something that came to my mind from some old readings, maybe it changed with some patches?

Robert



2b v !2b -> ?

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