Re: Detailed mineral mining table |
Wed, 03 October 2007 19:43 |
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m.a@stars | | Commander | Messages: 2765
Registered: October 2004 Location: Third star to the left | |
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yartrebo wrote on Wed, 03 October 2007 20:54 | I've been looking at those suspiciously similar numbers (125kT for 100+, and the 12,500kT factor for the ln() formula), and it's hit me that the ln() is not needed.
The derivative of ln(x) is quite simply 1/x, and 12,500/100 equals exactly 125kT.
With this in mind, I've revised the formula and it now has no floating point math needed:
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Now *that* is extremely interesting!
It makes a lot of sense too, given the Jeffs' penchant for all-integer math.
So many Stars, so few Missiles!
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