| Re: Mineral Extraction Timetables |
Wed, 17 December 2003 21:15   |
|
 LEit |
 | Lt. Commander |
Messages: 879
Registered: April 2003
Location: CT | |
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| alexdstewart wrote on Wed, 17 December 2003 18:06 |
Care to expand on it a little? This formula looks suspiciously just like the first formula I tried  . And I THINK it doesn't work. However I get the feeling that it is at least in the right direction.
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The ^2 means squared.
1250000/conc^2
So for 100 concentration, it will take 1250000/100^2 or 125 mine years to drop the concentration by 1.
At a concentration of 100, it's the same as the manual, at lower concentrtion, you it slows down a lot, the numbers match your test numbers very well.
Integrals might matter, but the formual is not continous. In other words, if you have 2500 mines and 100 min concentration, you will drop the concentration by 20 after mining the full year at 100. Continous would be mining for 125 mines at 100, and then at 99, and so on...
What you probably need is a sum of individual years.
- LEitReport message to a moderator
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