| Minefield collision calculation |
Sun, 31 May 2009 17:06  |
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 Mark Hewitt |
 | Master Chief Petty Officer |
Messages: 105
Registered: June 2006
Location: Calgary, Alberta, Canada | |
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I've read that there's a percentage per ly per warp over the safe speed, eg. 0.3% for standard mines, but how is this calculated?
Is the percentage x #warp over, e.g 1.5% for standards at warp 9, checked every ly? Or is there a cumulative effect?
Thanks!
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| Re: Minefield collision calculation |
Sun, 31 May 2009 19:21  |
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| neilhoward | 
 | Commander |
Messages: 1112
Registered: April 2008
Location: SW3 & 10023 | |
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Perhaps one of these links will be of some help.
Guts Formula on gible's Wiki.
The Academy: iztok explains formula, here on AH.
Chris Stott at rec.games.computer.stars
The same Best Speed Analysis at Starsfaq
edit: lol gible
(edit by Ron, fixed URL)
[Updated on: Tue, 25 January 2011 21:24] by Moderator
By the time you realize how steep the curve is, you will be using five types of calculus to get to the market. You will then need three different calculators to perform what you once considered basic arithmetic.Report message to a moderator
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| Re: Minefield collision calculation |
Sun, 31 May 2009 19:37 |
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From Guts of Minefields:
Collisions
*The formula for hitting a minefield per ly: (current warp speed - safe warp speed) * chance per ly of a hit
*Each ly traveled through a minefield is checked separately
*If traveling through overlapping fields, to-hit rolls will only be made vs one of the fields (randomly selected at start of movement).
You may also be interested in Analysis of best speed in minefields
Edit: heh Snap!
(edit by Ron, fixed URL)
[Updated on: Tue, 25 January 2011 21:24] by Moderator
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| Re: Minefield collision calculation |
Mon, 01 June 2009 02:41 |
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| iztok |
| Commander |
Messages: 1206
Registered: April 2003
Location: Slovenia, Europe | |
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Hi!
| gible wrote on Mon, 01 June 2009 01:37 |
*The formula for hitting a minefield per ly: (current warp speed - safe warp speed) * chance per ly of a hit
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I have a "gut feeling" that the presented formula isn't complete.
Some time ago while I've been testing minefields' chaff-sweeping, I ran into some peculiar mine-hit results. I had more than just one minefield, and when I ran some 100 chaff into each of them, I noticed that sometimes results were different from what my spreadsheet calc was predicting. It happened with most minefields in the same turn. Most of them were noticeably under- or over-sweeped. In that case "noticeably" means ~5% less or more chaff was affected (destroyed or survived).
Yes, I know the hit-probabilities are random. But with 500 random events with the same probability, they should be spread under a "bell curve" with the peak at its expected value. And the probability, that the peak would "shift" 5% off expected value in just some turns, should be minimal.
I'm still too lazy to dive into that probabilities' calculus, but my "gut feeling", that there's more in that formula, that meets the eye, remains. 
BR, Iztok
[Updated on: Mon, 01 June 2009 02:42] Report message to a moderator
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